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1231_Mechanics Homework Mechanics of Materials Solution

# 1231_Mechanics Homework Mechanics of Materials Solution -...

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Unformatted text preview: 10.43 A 3.5-m-lcng steel tube having the cross section and properties shown is used as a colmnn. For the grade of steel used 01' = 250 MPaland E = 200 GPa. Knowing that a factor of safety of 2.6 with respect to permanent deformation is required, determine the allowable load P when the eccentricity e is (a) 15 mm. (b) 7.5 mm. (Hint: Since the factor of safety must be applied to the load P, not to the stress, use Fig. 10.24 to determine Py). PROBLEM 10.43 SOLUTION A = 31100 Ho“ mz Y‘= 148.3 Ho's" 5 Le’ 3-5M l‘ﬁ‘ﬁﬁjjaﬂ 2' 72.6% I = 7.93 x 1045 m‘ r = 48.3 mm c:- 131= 63.5mm 2 15‘ 63.5) (a) e = 15mm eff-i =LZT)sgs_r— =' 0.40829 Using iii-3J0.“ wHk Le/w mus amt ec/r“=o.‘lo€2‘? PIA = mans MP4. = "Iv-75m" Po— PrUtumsuo‘ “snow-(0") ‘-' HMHD’ N ,‘ 3 ”sins irate/+0» o'F Sucre—{j P,” T 5&1?— = ISQ’IOSN = [8‘1 kl) ‘ (In) e: 7.5 mm 5%- =Q=§—§E;‘,’3—if—2 = 0.20415 05mg F.-3. 10.24 m“. L./r~= 72.46 amt ec/r‘r 0.2mm PM = 17512 H99. = 175.2 xIO‘ Pa. :F' = (.175. 2 xlD‘XB‘ioo trio-6) '-‘ 5‘16 x103 N Using 'ch‘t‘or- of safety. ' Ru: 1' 5%2123' - 22?KI£>1 N = 2,2914” .‘ ...
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