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1243_Mechanics Homework Mechanics of Materials Solution

# 1243_Mechanics Homework Mechanics of Materials Solution -...

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Unformatted text preview: 10.55 Axial loads of magnitude P = 175 kN are applied to a int located on the x PROBLEM 10-55 axis at a distance e = 12 mm ﬁ'om the geometric axis of the W120 x 44.8 rolled-steel column AB. Knowing that up = 2.50 MPa and E = 200 GPa,. determinerthe factor of safety with respect to yield. (Hint: Since the factor of safety must be applied to the load P, not to the stresses, use Fig. 10.24 to determine Pr.) SOLUTION For w mums A= 5720 m" ) v3: 35.! mm [42:33:30 W... Le/v‘ = 108.26 a: bi: L‘E—aw'ltlunm (2:1me \$2- : Egg—Q}? 0.72077 Usina H3 lo.2'l wC‘i'L l.../v‘= (08.74% am! \$3 = 0.72077 WA = 90.37 MPa. = 510.3?KIO‘ N/m‘ Pp AB/A = (5720«10")(9o.37w:o‘) -' 517x103 N 2 5:? 1w .7 '25.: %=%§r 2.67; ....‘ 10.55 Axial loads of magnitude P = 175 kN are applied to a point located on the x axis at a distance e = 12 mm ﬁ-orn the geometric axis of the W250 x 44.8 rolled-steel column AB. Knowing that or =' 250 MP3 and E = 200 GPa. determine the factor of safety with respect to yield. (Hint: Since the factor of safety must be applied to the load P, not to the stresses, use Fig. 10.24 to determine Pr.) 10.56 Solve Prob. 10.55, assuming that e = 16 mm and P = 155 kN. SOLUTION Fol" W250‘5‘i‘i8 A=S7ZO mum'-J '(‘JZ 35.1mm L: = 3800 um- LQIV‘ = “38.26 Cfgr=¥=74mm etlémm g9 _ “an?” _ v1 " (35“); ‘ O. ‘IGIOS Using 9-3 10.24 MM. Le/r=108.26 mi %% memos B/A = 3:. l7 "Pa. r 81.17 u/m‘ ﬁr = Amt/l“:(5720:10")C8L17xlo‘3 .- Ltcurxlos N z 4gq w _ P .. ‘i'é‘l _ RS- 1; - ﬁg ~ 3.00 ‘ ...
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