Unformatted text preview: 10.55 Axial loads of magnitude P = 175 kN are applied to a int located on the x
PROBLEM 1055 axis at a distance e = 12 mm ﬁ'om the geometric axis of the W120 x 44.8 rolledsteel
column AB. Knowing that up = 2.50 MPa and E = 200 GPa,. determinerthe factor of
safety with respect to yield. (Hint: Since the factor of safety must be applied to the
load P, not to the stresses, use Fig. 10.24 to determine Pr.) SOLUTION
For w mums A= 5720 m" ) v3: 35.! mm
[42:33:30 W... Le/v‘ = 108.26
a: bi: L‘E—aw'ltlunm (2:1me
$2 : Egg—Q}? 0.72077 Usina H3 lo.2'l wC‘i'L l.../v‘= (08.74% am! $3 = 0.72077
WA = 90.37 MPa. = 510.3?KIO‘ N/m‘
Pp AB/A = (5720«10")(9o.37w:o‘) ' 517x103 N 2 5:? 1w .7
'25.: %=%§r 2.67; ....‘ 10.55 Axial loads of magnitude P = 175 kN are applied to a point located on the x
axis at a distance e = 12 mm ﬁorn the geometric axis of the W250 x 44.8 rolledsteel
column AB. Knowing that or =' 250 MP3 and E = 200 GPa. determine the factor of
safety with respect to yield. (Hint: Since the factor of safety must be applied to the
load P, not to the stresses, use Fig. 10.24 to determine Pr.) 10.56 Solve Prob. 10.55, assuming that e = 16 mm and P = 155 kN. SOLUTION Fol" W250‘5‘i‘i8 A=S7ZO mum'J '(‘JZ 35.1mm L: = 3800 um LQIV‘ = “38.26
Cfgr=¥=74mm etlémm
g9 _ “an?” _ v1 " (35“); ‘ O. ‘IGIOS Using 93 10.24 MM. Le/r=108.26 mi %% memos
B/A = 3:. l7 "Pa. r 81.17 u/m‘ ﬁr = Amt/l“:(5720:10")C8L17xlo‘3 . Ltcurxlos N z 4gq w _ P .. ‘i'é‘l _
RS 1;  ﬁg ~ 3.00 ‘ ...
View
Full Document
 Summer '10
 STAFF

Click to edit the document details