Unformatted text preview: 10.74 A lSkip centric loed is applied to a rectangular sawn lumber column of 22ﬁ
PROBLEM 10.74 effective length. Using sewn lumber for which the adjusted allowable stress for compression parallel to the grain is ac = 1050 psi and knowing that E = 10 X 10‘ psi. determine the smallest cross section that can be used for the column if b = 2d. SOLUTION Saw» mourn ice? C: 0.8 K; = 0.?)
6c = 1050 Psi E = Iowo‘ 1’5" 20!“ L=224r+ = zen: ASSUMEJ C? = as 5J1 "' Sac? = (i050)(05) = 525 Psi
Pku=62uA = 26Lual" —/..__... =’_L3__0_02__‘?‘L868: .
d  2 '26'.” "' W 4.“, in, PM!
6'.“
_ ._ 39;; = go3)§:ouo‘) * swo‘ , Sag/6“,, = 0.7023 _ 1+5ce/62_ 1+(61g/6‘ 2 64/6; _
3”“ C!" T— i—T—Q) "—5—” *' 056‘“ ReSuPi’s. o‘i‘ simipaw “in‘aﬁs are summqv‘i'zed in He +mUe béjou). ...
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