1255_Mechanics Homework Mechanics of Materials Solution

# 1255_Mechanics Homework Mechanics of Materials Solution -...

This preview shows page 1. Sign up to view the full content.

This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: 10.74 A lS-kip centric loed is applied to a rectangular sawn lumber column of 22-ﬁ PROBLEM 10.74 effective length. Using sewn lumber for which the adjusted allowable stress for compression parallel to the grain is ac = 1050 psi and knowing that E = 10 X 10‘ psi. determine the smallest cross section that can be used for the column if b = 2d. SOLUTION Saw» mourn ice? C: 0.8 K; = 0.?) 6c = 1050 Psi E = Iowo‘ 1’5" 20!“ L=224r+ = zen: ASSUMEJ C? = as 5J1 "' Sac? = (i050)(0-5) = 525 Psi Pku=62uA = 26Lual" —/..__... =’_L3__0_02__‘?‘L868: . d - 2 '2-6'.” "' W 4.“, in, PM! 6'.“ _ ._ 39;; = go-3)§:ouo‘) * swo‘ , Sag/6“,, -= 0.7023 _ 1+5ce/62_ 1+(61g/6‘ 2 6-4/6; _ 3”“ C!" T— i—T—Q) "—5—” *' 056‘“ ReSuPi’s. o‘i‘ simipaw “in‘aﬁs are summqv‘i'zed in He +mUe béjou). ...
View Full Document

{[ snackBarMessage ]}

### What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern