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1298_Mechanics Homework Mechanics of Materials Solution

# 1298_Mechanics Homework Mechanics of Materials Solution -...

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Unformatted text preview: PROBLEM I 0. 1 25 (L) {zone-Tr. 6- = 7 I ~” eun‘ P.” = 6“”A = 10.125 Bar AB is ﬁve at its end/1 and ﬁxed at its base B. Determine the allowable centric load P if the aluminum alloy is (a) 6061-T6, ((3) 2014-16. SOLUTION A = (30100) = 300 mt: 30o x to" pm“ “(30300) 2. So no ’Mn" _l:I _’Z. Song _ Y‘Wn 30° - 2.887 MM Lg- - =c21ces)- no m L—rg =58.28 (by? 6061 -T6 L/r e 66 6...; = \‘32 - 0.848LL/ﬂ = :39 —(o.3es)(53.533 .— 87.‘| M'Pé. Pm = 64A = (37.9¥l0‘)(300xlo") = gun to” N = 26.4 W LN >55 " _ snuo‘ _ - (58.88)‘ — 107.3 MP4 (I07.3xio‘)(aooxlo“l= 32.2xlo’N = 32.2 W ...
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