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1348_Mechanics Homework Mechanics of Materials Solution

# 1348_Mechanics Homework Mechanics of Materials Solution -...

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Unformatted text preview: PROBLEM 11.54 ' PSI-ea _ (7352)“(15) : 17750 J l: U“ 25‘“ Am " (zMnuo‘Keaenxlo-ﬁ) " ‘ fE A“ = 3&0“; r 113. 907 MM: = H3339? x10“ m" _ REL“ _ gmnzcn- = 6. q J ‘. U“ ‘ zEmAm ' (2Ywswoﬁxusawno") '°‘ 7 IE DH 2 Had + U‘B ‘.'.: 28.32}, J- E Correspona't'nj epona AM" All! ﬁPmAm ‘7 Um ' 2U... _ mam“) _ .3 AM PM ’ 7351 "’ 7- '2 XIO M [[0 Fajlin-J cks'lanu! h = O.€+ 7. 12*10-3 = 0.607l7. Mn. E Work 0? weerf = UM Wk = .mgh = U... 11.54 Collar D is released ﬁ‘om rest in the position shown and is stopped by a small plate attached at end C of the vertical rod ABC. Determine the mass of the collar for which the maximum normal stress in portion BC is 125 MP3. SOLUTION Bronze E = 105 GP». 12-mm diameter Pop’l‘ﬁ'on 'BCI 6h '5 IZS‘XIO‘ Pa. Aluminum :- Q31. =' 63. El? MMl = GS.GI7 NM)-a m2 E=7OGPa A“ %( 9-mmd1ameter PM :- 6; AB; 2: 7952 N Corresponding 5+V‘m’n energy 3h ‘ 19-30(0-907'2) ...
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