{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

1430_Mechanics Homework Mechanics of Materials Solution

# 1430_Mechanics Homework Mechanics of Materials Solution - f...

This preview shows page 1. Sign up to view the full content.

This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: f.-. I 11 .01 A red consisting of n elements, each of which is homogeneous and of uniform cross section, is subjected to a load P applied at its free end. Elementn Elementi Element]. The length of element i is denoted by L, and its diameter by d.. (a) Denoting PROBLEM 1LC1 by E the modulus of elasticity of the material used in the rod, write a computer program that can be used to determine the strain energy acquired by the rod and the defamation measured at the free end. (b) Use this program to deter- mine the strain energy and deformation of the rods of Probs. 11.9 and 11.12. SOLUTION [Ax 7:54,; P g”; [ For? Fﬁcﬁ‘ Farmer]? EN??? 1‘2 («my D; ,— P (maven Noe/wet sweets: u a .- T C 2 L - glee/N Lava/MY: U. = _E__f_ ‘ Z flit: 57mm» 5”"?de WEIW'TQ __ t: q“ z! 7B 74:. 5-7941»; 585%?6 ‘r OPP/6‘71? 77/120Udﬁ 7, 4.21:”; 1:”; U 7 u + U3. 7074; DE Fawn TIM I _ . =_.._2” EPA-U . A P Preteen/w ou7gu7’ Problem 11 . 9 Axial load a 8.000 kipe Modulus of elasticity = 29 it 10‘s psi Element Length delta L Stress Strain Energy Strain Energy Density in. in. kei in-lb 1b-in./in."3 1 24.000 0.022 26.08 86.32 11.72 2 36.000 0.022 18.11 89.92 5.65 Total Strain Energy :- 176.24 in-lb Total Detormation .. 0.0441 in. Problem 11 . 12 Axial loud :- 25.000 kN Modulus of elasticity = 200 GPa Element Length delta 1:. Stress Strain Energy Strain Energy Density in mm MPa J kJ/m"3 1 0.80 0.497 124.34 6.22 38.65 2 1.20 0.477 79.58 5.97 15.83 Total Strain Energy = 12.1853 J Total Defamation - 0.9748 mm ...
View Full Document

{[ snackBarMessage ]}