Lecture Slides 16 - AMS 210 Applied Linear Algebra AMS 210...

Info icon This preview shows pages 1–6. Sign up to view the full content.

View Full Document Right Arrow Icon
AMS 210: Applied Linear Algebra November 10, 2009 AMS 210
Image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Topics Today Problem Set 7 Linear Regression: ˆ y = qx and ˆ y = qx + r Nonlinear Regression Linear Models in Chemistry AMS 210
Image of page 2
Problem Set 7 Grades and solution available on Blackboard. Mean of 74, median of 78, and standard deviation of 18. AMS 210
Image of page 3

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Linear Regression Method of fitting parameters of a linear model based on data. Linear Regression Model: Given a set of points ( x 1 , y 1 ) , ( x 2 , y 2 ) , . . . , ( x n , y n ), find constants q and r such that the linear relation ˆ y i = qx i + r gives the best possible fit for these points. Notationally, ( x i , ˆ y i ) is the estimate for ( x i , y i ). Multilinear regression finds several q i s corresponding to different variables (that is, multivariable linear regression); nonlinear regression fits to equations that aren’t linear. This course describes only simple, linear regression, which corresponds to the equation above. However, some nonlinear problems can be transformed to become linear problems. AMS 210
Image of page 4
Using the Model ˆ y = qx A restricted linear regression model: given a set of points ( x 1 , y 1 ) , ( x 2 , y 2 ) , . . . , ( x n , y n ), find a constant q such that the linear relation ˆ y i = qx i gives the best possible fit for these points.
Image of page 5

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Image of page 6
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern