Chapter+9+Student+Overheads

# Chapter+9+Student+Overheads - Polyprotic Acid-Base...

This preview shows pages 1–5. Sign up to view the full content.

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: Polyprotic Acid-Base Equilibria K a1 = 1.39 x 10-2 = [H + ][HSO 3- ] [H 2 SO 3 ] K a2 = 6.73 x 10-8 = [H + ][SO 3 2- ] [HSO 3- ] K b1 = K w K a2 = [OH- ][HSO 3- ] [SO 3 2- ] K b2 = K w K a1 = [OH- ][H 2 SO 3 ] [HSO 3- ] Polyprotic Acid-Base Equilibria K a1 = 7.11 x 10-3 = [H + ][H 2 PO 4- ] [H 3 PO 4 ] K a2 = 6.34 x 10-8 = [H + ][HPO 4 2- ] [H 2 PO 4- ] K a3 = 4.22 x 10-13 = [H + ][PO 4 3- ] [HPO 4 2- ] K b1 = K w K a3 = [OH- ][HPO 4 2- ] [PO 4 3- ] K b2 = K w K a2 = [OH- ][H 2 PO 4- ] [HPO 4 2- ] K b3 = K w K a1 = [OH- ][H 3 PO 4 ] [H 2 PO 4- ] Polyprotic Acid-Base Equilibria Step 1: Determine the form (acidic, intermediate, basic) of the polyprotic species given in the problem. Step 2: Calculate [H + ] based on the form (acidic, intermediate, basic) of the polyprotic species used to prepare the solution. Step 3: Use the equilibrium expressions and the calculated [H + ] to calculate the concentrations of the other polyprotic species in the solution. Polyprotic Acid-Base Equilibria Step 1:...
View Full Document

## This note was uploaded on 12/06/2011 for the course CHEM 241 taught by Professor Tiani during the Fall '08 term at UNC.

### Page1 / 17

Chapter+9+Student+Overheads - Polyprotic Acid-Base...

This preview shows document pages 1 - 5. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online