Chapter+9+Student+Overheads

Chapter+9+Student+Overheads - Polyprotic Acid-Base...

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Unformatted text preview: Polyprotic Acid-Base Equilibria K a1 = 1.39 x 10-2 = [H + ][HSO 3- ] [H 2 SO 3 ] K a2 = 6.73 x 10-8 = [H + ][SO 3 2- ] [HSO 3- ] K b1 = K w K a2 = [OH- ][HSO 3- ] [SO 3 2- ] K b2 = K w K a1 = [OH- ][H 2 SO 3 ] [HSO 3- ] Polyprotic Acid-Base Equilibria K a1 = 7.11 x 10-3 = [H + ][H 2 PO 4- ] [H 3 PO 4 ] K a2 = 6.34 x 10-8 = [H + ][HPO 4 2- ] [H 2 PO 4- ] K a3 = 4.22 x 10-13 = [H + ][PO 4 3- ] [HPO 4 2- ] K b1 = K w K a3 = [OH- ][HPO 4 2- ] [PO 4 3- ] K b2 = K w K a2 = [OH- ][H 2 PO 4- ] [HPO 4 2- ] K b3 = K w K a1 = [OH- ][H 3 PO 4 ] [H 2 PO 4- ] Polyprotic Acid-Base Equilibria Step 1: Determine the form (acidic, intermediate, basic) of the polyprotic species given in the problem. Step 2: Calculate [H + ] based on the form (acidic, intermediate, basic) of the polyprotic species used to prepare the solution. Step 3: Use the equilibrium expressions and the calculated [H + ] to calculate the concentrations of the other polyprotic species in the solution. Polyprotic Acid-Base Equilibria Step 1:...
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Chapter+9+Student+Overheads - Polyprotic Acid-Base...

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