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Chapter+22+Student - Solvent-Solvent Extraction CASE I: You...

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Solvent-Solvent Extraction
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CASE I: You have an analyte (A) in 100 mL of water. You perform one solvent-solvent extraction using 300 mL of hexane. How much analyte is left behind in the water phase? K = 3.0 for A between water and hexane. CASE II: What if you perform the same extraction as in Case I, except now you carry out 3 extractions using 50 mL of hexane? How much analyte is left behind in the water phase? K = 3.0 for A between water and hexane.
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CASE III: What about 6 extractions using 50 mL of hexane? How much analyte is left behind in the water phase? K = 3.0 for A between water and hexane. IN GENERAL:
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pH Effects in Solvent-Solvent Extractions
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K = 3.0 V org = 50 mL Solution buffered to pH 6.00 V aq = 100 mL K a = 6.28 x 10 -5 q = ? pH Effects in Solvent-Solvent Extractions Example:
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Lipid Bilayer (Phospholipids) Aqueous Solution Aqueous Solution Organic Phase Stomach pH ~ 1-3 Blood pH ~ 7.4 Drug Transport (i.e., Aspirin; Acetylsalicylic Acid) COOH O O pKa = 3.5 pH Effects in Solvent-Solvent Extractions
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Chromatography Figure 22-5: Daniel C. Harris, Quantitative Chemical Analysis , 8 th edition.
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Quantitative Chemical Analysis , 8 th edition. Chromatography: The Chromatogram
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Chapter+22+Student - Solvent-Solvent Extraction CASE I: You...

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