MSB Homework1 Answer - Answer for homework #1 (chapter 3)...

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Answer for homework #1 (chapter 3) 2. a. b. 1) t Y tY From Table 3.1 with n = 7, Σ t = 28, Σ t 2 = 140 1 19 19 2 18 36 3 15 45 4 20 80 5 18 90 6 22 132 7 20 140 132 542 For Sept., t = 8, and Y t = 16.86 + .50(8) = 20.86 (000) 2) Solutions (continued) 3) Month Forecast = F(old) + .20[Actual – F(old)] April 18.8 = 19 + .20[ 18 – 19 ] May 18.04 = 18.8 + .20[ 15 – 18.8 ]
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June 18.43 = 18.04 + .20[ 20 – 18.04 ] July 18.34 = 18.43 + .20[ 18 – 18.43 ] August 19.07 = 18.34 + .20[ 22 – 18.34 ] September 19.26 = 19.07 + .20[ 20 – 19.07 ] 4) 20 5) .6 (20) + .3(22) + .1(18) = 20.4 c. Probably trend because the data appear to vary around an average of about 19 [18.86]. d. Sales are reflective of demand (i.e., no stockouts or backorders occurred).
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This note was uploaded on 12/06/2011 for the course MSB 234 taught by Professor Nam during the Spring '11 term at Korea Advanced Institute of Science and Technology.

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MSB Homework1 Answer - Answer for homework #1 (chapter 3)...

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