# Summary9 - Summary Lecture 9 Newton’s Law of Gravity...

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Unformatted text preview: Summary Lecture 9 Newton’s Law of Gravity Newton’s Law of Gravity Force of Gravity Directed along the line connecting the 2 masses. Always attractive. Always attractive m1m2 FG = G r2 Universal Gravitational Constant G = 6.67 x 10-11 Nm2/kg2 Apparent Weight Fnet = FN-mg 2nd Law: FN –mg = ma Or (FN = apparent weight) FN = m(g+a) Drawings Courtesy of L. Gladding RECIPE: For each body in the problem – Draw the free body diagram including all forces acting ON this body – Define your coordinate system (positive x, positive y) – If necessary, split up forces in horizontal and vertical components (x and y) → → – Determine the net force Fnet = ΣF separately for x and y, if necessary: FNet x = ∑ Fx FNet y = ∑ Fy – Apply Newton’s second law → → Fnet = m a separately for x and y, if necessary: FNet x = ma x FNet y = ma y – m is the mass of this body a is the acceleration of this body Solve equations for unknowns ...
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Summary9 - Summary Lecture 9 Newton’s Law of Gravity...

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