10_1425_web_Lec_23_Statics

10_1425_web_Lec_23_Statics - More Angular Momentum, then...

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More Angular Momentum, then Statics Physics 1425 Lecture 23 Michael Fowler, UVa
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Vector Angular Momentum of a Particle A particle with momentum is at position from the origin O. Its angular momentum about the origin is This is in line with our definition for part of a rigid body rotating about an axis: but also works for a particle flying through space . p r Lrp = ×  Viewing the x -axis as coming out of the slide, this is a “right-handed” set of axes: ˆ ˆˆ ij k ×= + p r = × O x z y m
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Clicker Question A particle moves along a straight line at constant speed. The line does not pass through the origin. Is the particle’s angular momentum about the origin constant? A. Yes B. No
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Rotational Motion of a Rigid Body For a collection of interacting particles, we’ve seen that the vector sum of the applied torques, and the being measured about a fixed origin O. A rigid body is equivalent to a set of connected particles, so the same equation holds. It is also true (proof in book) that even if the CM is accelerating , / i i dL dt τ = L i CM CM / dL dt =
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A dumbbell (two small masses at the ends of a light rigid rod) is mounted on a fixed axle
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This note was uploaded on 12/07/2011 for the course PHYSICS 1425 taught by Professor Michaelfowler during the Spring '10 term at UVA.

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10_1425_web_Lec_23_Statics - More Angular Momentum, then...

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