This preview shows pages 1–3. Sign up to view the full content.
This preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview: o
o 2 3 4 x(m) (b) When 10 seconds have passed on the rocket's clock, only 6 seconds have passed on
the laboratory clock. Solutions to HW 1: Ch. 1 – 18, 23, 27, 43; Ch. 2 – 1, 4, 5, 8
118. (a)
U' =0 U~ =0 x y x'
v
x = U
x U'
x +v 1 + vU.: O+V ==V
Ic
1+ 0
2 (Equation 123) 7 Comments:
This version of the solution is done in the pion frame. This could also be done in the lab frame to get the
same solution using time dilation (from part b).
t = 50 m / 0.92c = 1.81 x 107 s (travel time of pions in lab frame)
N(t) = N0et/τ = (50000)e(181/66.3) = 3260
(Note, the text solution rounds time to 7 ns, if you keep 2 significant digits 7.1 ns, you get 3260) Calculation for part (c) is incorrect: W21 = 346 MeV = 5.54 x 10 11 J ...
View
Full
Document
This note was uploaded on 12/07/2011 for the course PHYS 2200 taught by Professor Jjdong during the Fall '08 term at Auburn University.
 Fall '08
 jjdong

Click to edit the document details