Lecture14_Kim

# Lecture14_Kim - Lecture 14-1 Physics 241 Question 1 October...

This preview shows pages 1–5. Sign up to view the full content.

Lecture 14-1 Physics 241 – Question 1 – October 6, 2011 The magnetic force on the electron is along the +z direction, while the magnetic field is along y. Which of the following might be the direction of the electron’s velocity? a) along +x b) along y c) along +z d) along -z e) along -x x y z B

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
Lecture 14-2 Sources of Magnetic Fields 0 2 4 μ q v r dB πr 7 0 7 2 N 4 10 4 10 A Tm A         Permeability constant • Moving point charge: 0 2 4 μ I d l r Bits of current: I Biot-Savart Law The magnetic field “circulates” around the wire.
Lecture 14-3 3 Let’s calculate the magnetic field at the center of a circular loop ( radius R ) of wire carrying current We start with We can see that r = R and = 90 for every current element along the loop For the magnetic field from each current element we get Magnetic Field from a Current Loop (1) 00 22 ˆ sin 44 ids r ids dB dB RR   sin90 ids ids dB 

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
Lecture 14-4 4 Going around the loop, we can relate an angle to the current element by ds = Rd allowing us to calculate the magnetic field at the center of the loop This calculation only gives us information on the at the center of the loop Using other techniques, we can calculate the magnetic field
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

### Page1 / 16

Lecture14_Kim - Lecture 14-1 Physics 241 Question 1 October...

This preview shows document pages 1 - 5. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online