PHYS310_Exam2_solutions - PHYS 310: Exam2 October 19, 2011...

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Unformatted text preview: PHYS 310: Exam2 October 19, 2011 Name: Problem 1 (30 points). The initial conditions of a two-dimensional isotropic oscillator are as follows: A y x A y A x t 3 , , 4 , , = = = = = where is the angular frequency. (a) (20 points) Find x and y as functions of t (b) (5 points) Show that the motion takes place entirely within the rectangle of dimensions 2A and 10A. (5 points) Make a sketch of the path. ( 29 cos x A t = + , ( 29 sin x A t = - + from x = o , = from x A = o , cos x A t = ( 29 cos y B t = + , ( 29 sin y B t = - + 2 2 2 1 1 1 2 2 2 kB ky my = + o o with 4 y A = o , 3 y A = o and k m = : ( 29 2 2 2 2 2 2 1 16 9 25 B A A A = + = 5 B A = Then 4 5 cos A A = and 3 5 sin A A = - 1 1 4 3 cos sin 36.9 5 5 -- = =- = - o ( 29 5 cos 36.9 y A t =- o Since maximum x and y displacements are A and 5 A , respectively, the motion takes place entirely within a...
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This note was uploaded on 12/07/2011 for the course PHYS 310 taught by Professor Jones,m during the Fall '08 term at Purdue University-West Lafayette.

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PHYS310_Exam2_solutions - PHYS 310: Exam2 October 19, 2011...

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