ch3_solutions

ch3_solutions - 1 SOLUTION TUTORIAL 3 Chapter 3, Solution...

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Unformatted text preview: 1 SOLUTION TUTORIAL 3 Chapter 3, Solution 1. At node 1, 6 = v 1 /(8) + (v 1- v 2 )/4 48 = 3v 1- 2v 2 (1) At node 2, v 1- v 2 /4 = v 2 /2 + 10 40 = v 1- 3v 2 (2) Solving (1) and (2), v 1 = 9.143V , v 2 = -10.286 V P 8 = = = 143.9 v 2 2 1 10.45 W P 4 = =- v v 2 2 1 94.37 W P 2 = = = = 286.10 v 2 1 2 52.9 W Chapter 3, Solution 2 At node 1, v v 6 v v 2 1 1 1- +=-- 60 = - 8v 1 + 5v 2 (1) At node 2, v v 63 v 2 1 2- ++= 36 = - 2v 1 + 3v 2 (2) Solving (1) and (2), v 1 = 0 V , v 2 = 12 V 2 Chapter 3, Solution 5 Apply KCL to the top node. v v 20 v 30 =- +- v = 20 V Chapter 3, Solution 6 i 1 + i 2 + i 3 = 0 10 v v 12 v 2 =- + +- or v = 8.727 V Chapter 3, Solution 7 At node a, b a b a a a V V V V V V 3 6 10 5 10- = - + =- (1) At node b, b a b b b a V V V V V V 7 2 24 9 12- = =-- +- +- (2) Solving (1) and (2) leads to V a = -0.556 V, V b = -3.444V Chapter 3, Solution 8 i 1 + i 2 + i 3 = 0 v4 v 3 v v 1 1 1 =- +- + 4V 3 But 1 v 2 v = so that v 1 + 5v 1- 15 + v 1- v 8 1 = or v 1 = 15x5/(27) = 2.778 V, therefore v o = 2v 1 /5 = 1.1111 V Chapter 3, Solution 13 At node number 2, [(v 2 + 2) 0]/10 + v 2 /4 = 3 or v 2 = 8 volts But, I = [(v 2 + 2) 0]/10 = (8 + 2)/10 = 1 amp and v 1 = 8x1 = 8volts Chapter 3, Solution 14 At node 1, v 40 5 v v 1- =+- v 1 + v = 70 (1) At node 0, 20 v v 5 v v 1 + + =+- 4v 1- 7v = -20 (2) Solving (1) and (2), v = 20 V Chapter 3, Solution 15 4 Nodes 1 and 2 form a supernode so that v 1 = v 2 + 10 (1) At the supernode, 2 + 6v 1 + 5v 2 = 3 (v 3- v 2 ) 2 + 6v 1 + 8v 2 = 3v 3 (2) At node 3, 2 + 4 = 3 (v 3- v 2 ) v 3 = v 2 + 2 (3) Substituting (1) and (3) into (2), 2 + 6v 2 + 60 + 8v 2 = 3v 2 + 6 v 2 = 1 56 v 1 = v 2 + 10 = 1 54 i = 6v i = 29.45 A P 65 = = & = = 6 11 54 Gv R v 2 2 1 2 1 144.6 W P 55 = = & - = 5 11 56 Gv 2 2 2 129.6 W P 35 = = =- 3)2( G v v 2 2 3 L 12 W Chapter 3, Solution 16...
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This homework help was uploaded on 04/06/2008 for the course EE 112 taught by Professor All during the Fall '08 term at Cal Poly.

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ch3_solutions - 1 SOLUTION TUTORIAL 3 Chapter 3, Solution...

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