PHYS310_homework_07_solutions

PHYS310_homework_07_solutions - Homework set 7, due Monday,...

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1. 5.1 (20 points) 5.1 (a) The non-inertial observer believes that he is in equilibrium and that the net force acting on him is zero. The scale exerts an upward force, N r , whose value is equal to the scale reading --- the “weight,” W’, of the observer in the accelerated frame. Thus 0 0 N mg mA + - = r r r 0 5 0 4 4 g N mg mA N mg m N mg - - = - - = - = 5 5 4 4 W N mg W ′ = = = 150 . W lb ′ = (b) The acceleration is downward, in the same direction as g r 0 4 g N mg m - + = 3 4 4 W W W W ′ = - = 90 . W lb ′ = 2. 5.2 (20 points) (a) ( 29 cent F m r ϖ = - × × r r r r For r r r , 2 ˆ cent r F m r e = r 1 1 500 1000 s s π - - = = ( 29 2 6 2 ˆ 10 1000 5 5 cent r F e - = × × = r dynes outward (b) ( 29 2 2 4 1000 5 5.04 10 980 cent g F m r F mg = = = × 3. A r (a) (b) N r mg r
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This note was uploaded on 12/07/2011 for the course PHYS 310 taught by Professor Jones,m during the Fall '08 term at Purdue.

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PHYS310_homework_07_solutions - Homework set 7, due Monday,...

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