# APaqueouspractice0809answerkey - AP Chemistry Solution...

This preview shows pages 1–2. Sign up to view the full content.

AP Chemistry Solution Chemistry Practice Problems Name: ____________________________ Date: ____________ Period: _____ 1. Consider a 1.00L solution containing 85.5g Al 2 (SO 4 ) 3 (FW = 342.15) and 21.3g Na 2 SO 4 (FW = 142.06). What are the molar concentrations of the aluminum, sodium and sulfate ions? 1. mol Al 2 (SO 4 ) 3 = 85.5g/(342.15g/mol) = .250mol = 0.50mol Al and 0.75mol SO 4 2- mol Na 2 SO 4 = 21.3g/(142.06g/mol) = .150mol = 0.300mol Na and 0.150mol SO 4 2- [Al 3+ ] = 0.500mol/1.0L = 0.500M [Na + ] = 0.300mol/1.0L = 0.300M [SO 4 2- ] = (0.750mol + 0.150mol)/1.0L = 0.900M 2. The molecular equation is H 2 SO 4(aq) + Sr(OH) 2(aq) SrSO 4(s) + 2H 2 O (l) The total ionic equation is H + (aq) + HSO 4 - (aq) + Sr 2+ (aq) + 2OH - (aq) SrSO 4(s) + 2H 2 O (l) (or 2H + (aq) + SO 4 2- (aq) + Sr 2+ (aq) + 2OH - (aq) SrSO 4(s) + 2H 2 O (l) ) Since there are no spectator ions, the total and net ionic equations are the same . 3. Which of the following substances is a strong electrolyte in aqueous solution? NaCl CH 4 H 2 O CO CCl 4 NaCl. NaCl is a soluble ionic compound. The others either do not produce, or produce an extremely small number of ions (H 2 O). 4. A 25.00mL sample of an aqueous solution of Ba(OH) 2 requires 18.45mL of 0.01500M HCl (aq) for its neutralization. What is the molarity of the Ba(OH) 2 solution? moles of HCl used = .01845L(0.01500mol/L) = 2.77x10

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.