APaqueouspractice0809answerkey

APaqueouspractice0809answerkey - AP Chemistry Solution...

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AP Chemistry Solution Chemistry Practice Problems Name: ____________________________ Date: ____________ Period: _____ 1. Consider a 1.00L solution containing 85.5g Al 2 (SO 4 ) 3 (FW = 342.15) and 21.3g Na 2 SO 4 (FW = 142.06). What are the molar concentrations of the aluminum, sodium and sulfate ions? 1. mol Al 2 (SO 4 ) 3 = 85.5g/(342.15g/mol) = .250mol = 0.50mol Al and 0.75mol SO 4 2- mol Na 2 SO 4 = 21.3g/(142.06g/mol) = .150mol = 0.300mol Na and 0.150mol SO 4 2- [Al 3+ ] = 0.500mol/1.0L = 0.500M [Na + ] = 0.300mol/1.0L = 0.300M [SO 4 2- ] = (0.750mol + 0.150mol)/1.0L = 0.900M 2. The molecular equation is H 2 SO 4(aq) + Sr(OH) 2(aq) SrSO 4(s) + 2H 2 O (l) The total ionic equation is H + (aq) + HSO 4 - (aq) + Sr 2+ (aq) + 2OH - (aq) SrSO 4(s) + 2H 2 O (l) (or 2H + (aq) + SO 4 2- (aq) + Sr 2+ (aq) + 2OH - (aq) SrSO 4(s) + 2H 2 O (l) ) Since there are no spectator ions, the total and net ionic equations are the same . 3. Which of the following substances is a strong electrolyte in aqueous solution? NaCl CH 4 H 2 O CO CCl 4 NaCl. NaCl is a soluble ionic compound. The others either do not produce, or produce an extremely small number of ions (H 2 O). 4. A 25.00mL sample of an aqueous solution of Ba(OH) 2 requires 18.45mL of 0.01500M HCl (aq) for its neutralization. What is the molarity of the Ba(OH) 2 solution? moles of HCl used = .01845L(0.01500mol/L) = 2.77x10
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This note was uploaded on 12/07/2011 for the course CHEM 100 taught by Professor Feebeck during the Fall '10 term at Purdue University.

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APaqueouspractice0809answerkey - AP Chemistry Solution...

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