apchem chp4 suppws key - AP Chemistry Chapter 4: Chemical...

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AP Chemistry – Chapter 4: Chemical Equations and Stoichiometry Supplemental Worksheet Key 1. a. .24g PbS/239.27g/mol = .001mol multiply by 4mol H 2 O 2 /1mol PbS = .004mol H 2 O 2 = .137g H 2 O 2 b. 0.072g H 2 O/18.015g/mol = .004mol multiply by 1mol PbSO 4 /4mol H 2 O = .001mol PbSO 4 multiply by 303.268g/mol = .303g PbSO 4 2. a. 12.0g H 2 /2.0158g/mol = 5.95mol H 2 exists 74.5g CO/28.010g/mol = 2.66mol CO x 2mol H 2 /1mol CO = 5.32mol H 2 required H 2 in excess b. CO limits (see calculation above) c. 5.95mol - 5.32mol = .63mol x 2.0158g/mol = 1.27g H 2 leftover d. 2.66mol CH 3 OH x 32.042g/mol = 85.23g 3. Theoretical = 1.00mol ZnCl 2 x 136.29g/mol 136.29g % yield = 115g/136.29g = 84.4% 4. 1.760g CO 2 /44.01g/mol = .04mol CO 2 = .04 mol of C in hydrocarbon .900g H 2 O/18.16g/mol = .05mol H 2 O = .10mol H C (.04/.04) H (.10/.04) = CH 2.5 = C 2 H 5 5. 0.657g CO 2 /44.01g/mol = .015mol CO 2 = .015mol C = .015 mol CaCO 3 .015mol(100.09g/mol) = 1.50g CaCO 3 1.50g/1.605g = 93.46% mass percentage
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This note was uploaded on 12/07/2011 for the course CHEM 100 taught by Professor Feebeck during the Fall '10 term at Purdue University-West Lafayette.

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apchem chp4 suppws key - AP Chemistry Chapter 4: Chemical...

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