Unformatted text preview: 3.5 An incompressible fluid with density p flows steadin
past the object shown in Videu V3.7 and Fig. P35. The fluid
velheityl along the horizontal dividing srreamfine
(—aa 5 x 5 —a) is found to be V = V00 + afx). where a is
the radius of curvature of the front of the object and V0 is the
upstream velocity. {at} Determine the pressure gradient along
this streamline. (b) if the upstream pressure is .00. integrate the
pressure gradient to ebtain the pressure p{.r) for --W E x E -a.
{c} Show from the result of part {11) that the pressure at the stag-
nation peint (x = —a) is pa + pVfi/Z. as expected from the
Bernoulli equation. Dividing
streamline Stagnation
point I FIGURE 133.5 (a) %= 9V3} where V=V V(i+-a') Thus $7: §_|(“J_g_' {5) From parfffl) when X=—a 70} = goo—PMH + 5'3"] Xfldfl = {3, WWW Pram the Bernaut'fr' aged-{ion fl: + 72L? V0 1 .-; where V= V ”VU'i'ETaJ): 0 X‘ "It 77W, P, =" fl, @9914: as attracted. ...
View
Full Document
- Fall '10
- FredrickStern
-
Click to edit the document details