Class37_Ex2 - Solution: ( p + 20 psi ) ( p A ) h f = h = A...

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Solution: () ( ) 20 03 0 AA f pp s i p hh γγ + ⎡⎤ =−∆ =− + ⎢⎥ ⎣⎦ 20 144 30 16.2 62.4 ft × =− + 0 h ∆> , adverse pressure gradient and flow right to left 2 2 f LV hf Dg = 12 2 2 32.2 16.2 0.3629 35 2 8 02 f gh Vf ff LD −− ×× == = × 0.0004 s kD = Given 0.017
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