Class37_Ex3 - Solution: V12 p2 V22 + +z = + +z +h 2g 1 2g 2...

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Solution: 22 11 2 2 12 L pV p V zz h gg γγ ++ =++ + 2 2 LV f Dg =+ Since QV A = 2 4 Q V D π = 2 2 24 16 Q V D = 2 16 1 20 2 LQ f DDg = 2 5 2 16 1329 20 2 Q Df L f g == Given f , e.g., 0.02 f = 1.93 t = 3.43 Vf t s = 5 Re 5.5 10 VD ν × 0.015 s kD = 0.0175 f = from Moody diagram
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This note was uploaded on 12/08/2011 for the course MECHANICS 57:020 taught by Professor Fredrickstern during the Fall '10 term at University of Iowa.

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