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Class42_Ex5 - 9:11 A awn—diameter cork ball(36 m 0.21...

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Unformatted text preview: 9:11 A awn—diameter cork ball (36 m 0.21) iifiea to an object on the bottom of a river as is shown in Fig. ”.61. Esthnate the speed of the river current. Negiect the weight of the cable and the drag on it. For five Em” 1‘0 remain sfa‘lienary Z: 1'; =0 and, 2: F; =0 ThUS’ fl = 7603 30. or T: 03 and 60.530‘ E9 = W+T‘5,}y3o‘ Hence, f; ‘—'-' W+ «53 fan 30’, w/Jere Fé = €gV=(280%)(—§E(§2mf) dig D 3 0.30m and :: 0.585 kA’ w = a; ’9‘ 4%)347‘ :63) a; 771m, .1 o. 2160,1385 MI) 0.138534%” = 0. 029/ M! +05 fgflgg“ 50.026); MI Of‘ ((7: 0J8? NV, wfiere «5*: Q, 2"va =QUZ(5‘I)(999£%J(§[03M)11 .2 3, Hence 2 35-3 CDU N, where Ufi'égg 35.363312!»- /89 0?- CW2: 5.3.5 (ti ”9/”: 2519 ”M = W—W U ‘" 2 68X/05U V —6 1 '" - Hg: and IJZXIO if“ from H9, 9‘21 Cpl \V (3; Re Trial and error so/m‘ian for 17 -' flame CD J- ca/cu/a/e U from 5231/} and Re Pram £13.01); check CD from 5413), file gimp/i. fissumg CD = 0.5 M» V: 3.27131 ”R3 = 8.75x105—+ CD: 0.15 #05 fissume 6}, =0.15 ——-- U= 5.97 {1% “w Re 3 Lemar/05M Cb ~7- 0.20 $0.15 5» =0.” ...... U: 5.3; {g— m. Re :: L‘leIO‘m—b Co 2 0.19 (mm) 19550333 _. I” HUS, Lr*5.3l~§' “1'67. ...
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