week10tue

# Week10tue - ECE 410/510 Electric Vehicles Part I Electric Drives and Controllers Week 10 Tuesday March 8 1 Maseeh College of Engineering and

This preview shows pages 1–8. Sign up to view the full content.

Maseeh College of Engineering and Computer Science 3/8/11 1 ECE 410/510 - Electric Vehicles Part I – Electric Drives and Controllers Week 10 – Tuesday March 8

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
Electrical and Computer Engineering ECE 410 / 510 – Electric Vehicles I Hammerstrom/Butts Week 10 – March 8, 10 Tue: Finish batteries Thu: Review for final exam Lab 7 due Week 11 – FINAL EXAM, Tuesday March 15, 7:30-9:20, Same Room 3/8/11 2
Maseeh College of Engineering and Computer Science 3/8/11 3 Lab 5 Problem Solutions

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
Electrical and Computer Engineering ECE 410 / 510 – Electric Vehicles I Hammerstrom/Butts Problem 9-6 In a 2-pole, three-phase machine with N s =100, calculate and at a time t if at that time the stator currents are as follows (a) i a =10A, i b =-5A, i c =-5A; (b) i a =-5A, i b =10A, i c =-5A; (c) i a =-5A, i b =-5A, i c =10A Just do (a): 3/8/11 4 i s F s F s ( t ) = ( N s / 2) i s ( t ) i s ( t ) = i a ( t ) + i b ( t ) 120 + i c ( t ) 240 i a = 10 A , i b = i c = 5 A i s = 10 5 120 5 240 = 15 0 F s = 750 0 A turns
Electrical and Computer Engineering ECE 410 / 510 – Electric Vehicles I Hammerstrom/Butts Problem 10-6 A PMAC machine has 4 poles and three phases k T and k E are both 0.5 (MKS units) The stator inductance is 15 mH (neglect winding resistance) The motor is supplying a torque of 5 Nm at a speed of 5000 rpm in a balanced sinusoidal steady state Draw a phasor diagram showing and along with their calculated values 3/8/11 5 V a I a p = 4, ω m = 523.6 rad / s e = p 2 m = 1047.2 rad ( elect ) / s k T = T em ˆ I s = π 2 rlN s ˆ B r = 0.5 N m / A It's independent of p so ˆ I s = T em k T ˆ E m = rl N s p ˆ B ms , since = p 2 syn so ˆ E m = 2 rlN s syn ˆ B ms For a PMAC drive ˆ E m = ˆ E f ˆ B ms = ˆ B r syn = m ˆ E f = 2 rlN s ˆ B r m since k E = ˆ E f m = 0.5 V / rad ( mech ) / s ˆ E f = k E m

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
Electrical and Computer Engineering ECE 410 / 510 – Electric Vehicles I Hammerstrom/Butts 3/8/11 6 ˆ E f = k E ω m = 0.5 × 523.6 = 261.8 V ˆ I S = T em k T = 5 k T = 10 A , ˆ I a = 2 3 ˆ I S = 6.67 A If we assume θ i s t = 0 = 0 , then m (0) = 90 p / 2 = 45 , recall i s ( t ) = p 2 m ( t ) ± π 2 , i s ( t ) = p 2 m t = e t = 1047.2 × t rad i a ( t ) = ˆ I a cos( i s ( t )) = 6.67cos( is ( t )) I a = 6.67 0 A V a = E fa + j e L s I a = 261.8 + j 1047.2 × (15 × 10 3 ) × 6.67 0 V a = 282.0 21.83 V Few did the analysis of why k T and k E gave the right answers, but I didn’t take points off for that
Electrical and Computer Engineering ECE 410 / 510 – Electric Vehicles I Hammerstrom/Butts Lab 5 Comments Several people used Matlab to plot results for both problems, I would have preferred phasor notation for problem 9-6, but the problem description didn’t require it, so no points were subtracted, in phasor notation you notice

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

## This note was uploaded on 12/08/2011 for the course ECE 410 taught by Professor Maseeh during the Spring '11 term at Portland State.

### Page1 / 71

Week10tue - ECE 410/510 Electric Vehicles Part I Electric Drives and Controllers Week 10 Tuesday March 8 1 Maseeh College of Engineering and

This preview shows document pages 1 - 8. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online