midterm2solu

# midterm2solu - Midterm 2 Solution Problem 1. (a):...

This preview shows pages 1–2. Sign up to view the full content.

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: Midterm 2 Solution Problem 1. (a): Advantage: eliminate between-block variation. Disadvantage: loss of degree of freedom. (b): ¯ y ·· = 17 . 2+20 . 8+14 . 6 3 = 17 . 533 SS Block = a ∑ (¯ y · j- ¯ y .. ) 2 = 3(11 . 6667- 17 . 5333) 2 +3(18 . 6667- 17 . 5333) 2 + 3(28- 17 . 5333) 2 + 3(20 . 6667- 17 . 5333) 2 + 3(8 . 6667- 17 . 5333) 2 = 701 . 07 SS Trt = b ∑ (¯ y i ·- ¯ y ·· ) 2 = 5(17 . 2- 17 . 5333) 2 +5(20 . 8- 17 . 5333) 2 +5(14 . 6- 17 . 5333) 2 = 96 . 93 SS E = SST- SS Block- SS Trt = 41 . 73 H : τ 1 = τ 2 = τ 3 = 0 vs H 1 : at least one is not Use F-test to test H : F = MS Trt MS E = SS Trt / ( a- 1) SS E / ( a- 1)( b- 1) = 96 . 93 / 2 41 . 73 / 8 = 9 . 29. F . 05 (2 , 8) = 4 . 46, which is smaller than F . Therefore H is rejected. (c): CD = q . 05 ( a, ( a- 1)( b- 1)) √ (2) q MS E ( 1 b + 1 b ) = 4 . 04 · q 41 . 73 8 1 5 = 4 . 13 ¯ y 2 ·- ¯ y 1 · = 3 . 6 < CD ¯ y 1 ·- ¯ y 3 · = 2 . 6 < CD ¯ y 2 ·- ¯ y 3 · = 6 . 2 > CD Therefore catalyst A is not different from catalyst B, and catalyst A is not...
View Full Document

## This note was uploaded on 12/09/2011 for the course STAT 514 taught by Professor Staff during the Fall '08 term at Purdue University.

### Page1 / 3

midterm2solu - Midterm 2 Solution Problem 1. (a):...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online