41 - symrl41 filled - ME 575 Handouts LQR Design Example 2...

Info iconThis preview shows pages 1–4. Sign up to view the full content.

View Full Document Right Arrow Icon
ME 575 Handouts 1 ME575 Session 41: Symmetric Root Locus School of Mechanical Engineering Purdue University Slide 1 01 0 xx u 1 1 x(0) 0 ⎡⎤ =+ ⎢⎥ ⎣⎦ = ± TT 22 11 1 00 Vx Q x u R u d tx u d t ∞∞ = + ∫∫ 1T uR B P x =− LQR Design Example 2 ME575 Session 41: Symmetric Root Locus School of Mechanical Engineering Purdue University Slide 2 LQR Design Example 2 LQR Design Example 2 T1 T A PP AP B RBPQ0 +− + =
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
ME 575 Handouts 2 ME575 Session 41: Symmetric Root Locus School of Mechanical Engineering Purdue University Slide 3 LQR Design Example 2 LQR Design Example 2 ME575 Session 41: Symmetric Root Locus School of Mechanical Engineering Purdue University Slide 4 LQR Design Example 2 LQR Design Example 2 Time (sec.) Amplitude Initial Condition Results 0 1 2 3 4 5 6 7 -0.2 0 0.2 0.4 0.6 0.8 1 1.2
Background image of page 2
ME 575 Handouts 3 ME575 Session 41: Symmetric Root Locus School of Mechanical Engineering Purdue University Slide 5 LQR Design Example 2 LQR Design Example 2 Let ’s look at closed s look at closed
Background image of page 3

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Image of page 4
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 12/09/2011 for the course ME 575 taught by Professor Meckl during the Fall '10 term at Purdue University-West Lafayette.

Page1 / 8

41 - symrl41 filled - ME 575 Handouts LQR Design Example 2...

This preview shows document pages 1 - 4. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online