This preview shows page 1. Sign up to view the full content.
Unformatted text preview: x 2 0 for all real numbers x ? Proof. Suppose not. Then for every real number x , x 2 < 0. In particular, plugging in x = 3, we would get 9 < 0, which is clearly false. This contradiction shows that for every real number x , x 2 0....
View Full Document
- Fall '09