Unformatted text preview: x 2 ≥ 0 for all real numbers x ? Proof. Suppose not. Then for every real number x , x 2 < 0. In particular, plugging in x = 3, we would get 9 < 0, which is clearly false. This contradiction shows that for every real number x , x 2 ≥ 0....
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 Fall '09
 LARSON

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