Example 11-5 Solutions

Example 11-5 Solutions - Example 11.5 Given: Water vapor...

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Example 11.5 Given: Water vapor (1) P 1 = 3 MPa and T 1 = 300 ° C (2) constant volume process from State 1 to State 2 i.e. v 1 = v 2 (3) T 2 = 200 ° C (4) constant temperature process from State 2 to State 3 i.e. T 2 = T 3 (5) P 3 = 2.5 MPa Find: (1) Locate all states on T-v and P-v diagrams (2) v 1 , v 2 , v 3 (3) x at an appropriate state System Identification: The above system undergoes two processes Assumptions: (1) All states are in equilibrium Basic Equations: None. Need to look up property tables.
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Solution: In such problems, the most crucial part is to locate all states on appropriate property diagrams. In this case, we are going to use T-v and P-v diagrams along with the given information to fix all states. Remember: We need two independent properties to fix the state of a single component system completely! Our objective is always to know two independent properties at each state of the given system. Let’s begin with State 1:
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This note was uploaded on 12/11/2011 for the course ME 200 taught by Professor Gal during the Fall '08 term at Purdue.

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Example 11-5 Solutions - Example 11.5 Given: Water vapor...

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