ME200 - Lecture 240

# ME200 - Lecture 240 - 1 More on Second Law of...

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Unformatted text preview: 10/25/2010 1 More on Second Law of Thermodynamics ME 200 Thermodynamics I Purdue University , Dr. Tim Pourpoint – [email protected] Lecture 24 October 25 th , 2010 Lecture Outline Last Lecture: • Second Law of Thermodynamics • Absolute temperature scale: • Maximum performance parameters as described by Carnot (reversible) cycles: ME 200 ME 200 2 This Lecture: • Finish Example 23.1 • More on Carnot Cycle, Reversed Carnot Cycle (Examples) 10/25/2010 2 Example 23.1 • Two kilograms of water execute a Carnot power cycle. During the isothermal expansion, the water is heated until it is a saturated vapor from an initial state where the pressure is 40 bar and the quality is 15%. The vapor then expands adiabatically to a pressure of 1.5 bar while doing 491.5 kJ/kg of work. (a) Sketch the cycle on p ‐ v coordinates. (b) Evaluate the heat and work for each process, in kJ ( Q cycle = W cycle ME 200 ME 200 3 cycle cycle = 773 kJ). (c) Calculate the thermal efficiency (0.265). • Given: 2.0 kg of water execute a Carnot cycle Isothermal expansion: State 1 to State 2 p 1 = 40 bar 1 = 15% 2 = 100% Solutions for Example 23.1 p 1 40 bar, x 1 15%, x 2 100% Adiabatic Expansion: State 2 to State 3 p 3 = 1.5 bar, W 23 = +491.5 kJ/kg • Find: (a) Sketch the cycle on p ‐ v coordinates....
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ME200 - Lecture 240 - 1 More on Second Law of...

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