ME200_Exam2_Solution - First Name Solution Last Name CIRCLE...

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1 First Name Solution Last Name CIRCLE YOUR LECTURE BELOW: 7:30 a.m. 8:30 a.m. 10:30 a.m. 1:30 p.m. 3:30 p.m. Mongia Abraham Sojka Bae Naik ME 200 Exam 2 October 18, 2011 6:30 p.m. to 7:30 p.m. INSTRUCTIONS 1. This is a closed book examination. You are provided with an equation sheet and all needed property tables are provided. 2. Do not hesitate to ask the instructor if you do not understand a problem statement. 3. Start each problem on the same page as the problem statement. Write on only one side of the page. Materials on the back side of the page will not be graded. There are blank pages following problems 2 and 3 for your work. 4. Put only one problem on a page. Another problem on the same page will not be graded. 5. Label your system and list relevant assumptions for problems 2 and 3. 6. If you give multiple solutions, you will receive only a partial credit although one of the solutions might be correct. Delete the solution you do not want graded. 7. For your own benefit, please write clearly and legibly. Maximum credit for each problem is indicated below. 8. After you have completed the exam, at your seat put your papers in order . This may mean that you have to remove the staple and re-staple. Do not turn in loose pages . 9. Once time is called you will have three minutes to turn in your exam. Points will be subtracted for exams turned in after these three minutes. Problem Possible Score 1 30 2 30 3 40 Total 100
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2 First Name Solution Last Name Problem 1 (30 points) Show all work to receive credit. (a) What is the density (kg/m 3 ) of methane at pressure of 27.85 bar and temperature of 181.45 K? (15 points) Using Table A-1 for methane: Molecular Weight, M methane = 16.04 kg/kmol Critical Temperature, T critical = 191 K Critical Pressure, P critical = 46.4 bar At P = 27.85 bar and T = 181.45 K: Reduced Pressure: 27.85 bar 0.6 46.4 bar R critical P P P  Reduced Temperature: 181.45 K 0.95 191 K R critical T T T Using Fig. A-1, compressibility factor: 0.7 Z and methane Pv Z R T Specific volume:  3 kJ 8.314 kmol-K 0.7 181.45 K kg 16.04 m kmol 0.0236 27.85 100 kPa kg methane methane R ZT ZR T M v PP 
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This note was uploaded on 12/11/2011 for the course ME 200 taught by Professor Gal during the Fall '08 term at Purdue.

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ME200_Exam2_Solution - First Name Solution Last Name CIRCLE...

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