ANS_EX_4 - Swieter; p1 of 12 CHM1040 Answer to Exercise Set...

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Unformatted text preview: Swieter; p1 of 12 CHM1040 Answer to Exercise Set 4 QUESTIONS ON THE PROPERTIES OF LIGHT 1. m/s 10 x 2.9979 = c where c = or , = c 8 ν λ ν λ • a) m 10 x 5.89 = s 10 x 5.09 m/s 10 x 2.9979 = 7- 1- 14 8 λ b) m 10 x 3.5 = s 10 x 8.6 m/s 10 x 2.9979 = 5- 1- 12 8 λ c) m 10 x 1.5 = s 10 x 2.0 m/s 10 x 2.9979 = 1- 1- 9 8 λ 2. s _ J 10 x 6.6262 = h where c _ h = E or _ h = E and c = or , _ = c 34- λ ν λ ν ν λ a) s 10 x 1.7 = m 10 x 1.8 m/s 10 x 2.9979 = 1- 10 2- 8 ν J 10 x 1.1 = m 10 x 1.8 m/s) 10 x s)(2.9979 _ J 10 x (6.6262 = E 23- 2- 8-34 b) s 10 x 6.25 = m 10 x 4.80 m/s 10 x 2.9979 = 1- 15 8- 8 ν J 10 x 4.14 = m 10 x 4.80 m/s) 10 x s)(2.9979 _ J 10 x (6.6262 = E 18- 8- 8-34 c) s 10 x 9.83 = m 10 x 3.05 m/s 10 x 2.9979 = 1- 14 7- 8 ν J 10 x 6.51 = m 10 x 3.05 m/s) 10 x s)(2.9979 _ J 10 x (6.6262 = E 19- 7- 8-34 3. E c _ h = or c _ h = E and h E = or , _ h = E λ λ ν ν a) s 10 x 1.05 = s _ J 10 x 6.6262 J 10 x 6.95 = 1- 14 34--20 ν and, m 10 x 2.86 = J 10 x 6.95 m/s) 10 x s)(2.9979 _ J 10 x (6.6262 = 6- 20- 8-34 λ b) s 10 x 8.99 = s _ J 10 x 6.6262 J 10 x 5.96 = 1- 7 34--26 ν and, m 3.33 = J 10 x 5.96 m/s) 10 x s)(2.9979 _ J 10 x (6.6262 = 26- 8-34 λ c) s 10 x 3.02 = s _ J 10 x 6.6262 J 10 x 2.00 = 1- 18 34--15 ν and, Swieter; p2 of 12 m 10 x 9.93 = J 10 x 2.00 m/s) 10 x s)(2.9979 _ J 10 x (6.6262 = 11- 15- 8-34 λ 4. a) ... e therefor ; 1 = _ λ ν cm 10 x 6.67 = cm 10 m 1 x m 10 x 150 1 = _ 1- 7 2 12- ν This is in the X-ray region. b) ... e therefor ; _ _ c _ h = E ν J 10 x 7.946 = m 10 4000 x m/s 10 x 2.9979 x s J 10 x 6.6262 = E 20- 2- 8 34- • This is in the IR region. c) ... e therefor ; c = ν λ nm 10 x 2.00 = m 10 nm 1 x s 10 x 1.50 m/s 10 x 2.9979 = 2 9- 1- 15 8 λ This is in the UV region. d) ... e therefor ; c _ h = E λ J 10 x 2.0 = m 10 x 10 m/s 10 x 2.9979 x s _ J 10 x 6.6262 = E 24- 2- 8-34 This is in the MW region. e) ... e therefor ; h E = ν s 10 x 1.5 = s _ J 10 x 6.6262 J 10 x 1.0 = 1- 15 34--18 ν This is in the UV region. f) ... e therefor ; c = _ ν ν cm 10 x 4.00 = cm 10 m 1 x m/s 10 x 2.9979 s 10 x 1.20 = _ 1- 3 2 8 1- 14 ν This is in the IR region. Swieter; p3 of 12 X:\~Natsci\ADJUNCT\bhaskar\pdf\1041\ANS_EX#4.DOC 5. ... e therefor ; c _ h = _ h = E λ ν J/photon 10 x 05 3. or J 10 x 05 3. = m 10 x 650 m/s 10 x 2.9979 x s _ J 10 x 6.6262 = E 19- 6 19- 6 9- 8-34 J/mol 10 x 1.84 = mol photons 10 x 6.022 x photon J 10 x 05 3. = mole photons # x photon E = E 5 23-19 6 tot 6. J 10 x 3 1. = m 10 x 0.15 m/s) 10 x s)(2.9979 _ J 10 x (6.6262 = c _ h = E : rays X- 15- 2 9- 8-34 λ J 10 x 98 1. = m 10 x 1.00 m/s) 10 x s)(2.9979 _ J 10 x (6.6262 = c _ h = E : Microwaves 22- 6 3- 8-34 λ ! 10 x 6.7 = J 10 x 98 1. J 10 x 3 1....
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This note was uploaded on 12/11/2011 for the course CHM 1045 taught by Professor Staff during the Spring '10 term at Santa Fe College.

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ANS_EX_4 - Swieter; p1 of 12 CHM1040 Answer to Exercise Set...

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