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ANS_EX_7 - Swieter p 1 of 5 CHM1040 Answer to Exercise Set...

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Swieter; p 1 of 5 X:\~Natsci\ADJUNCT\bhaskar\pdf\1041\ANS_EX#7.DOC CHM1040 Answer to Exercise Set 7 QUESTIONS ON EQUATION WRITING 1. a. Inventory of 0.1 M HCl: [H 3 O + ] = 0.1 M , [Cl - ] = 0.1 M. Inventory of 0.1 M KOH: [K + ] = 0.1 M , [OH - ] = 0.1 M. Reaction: H 3 O + (aq) + OH - (aq) 2 H 2 O ( l ) Large Extent b. Inventory of 0.1 M HNO 3 : [H 3 O + ] = 0.1 M , [NO 3 - ] = 0.1 M. Inventory of 0.1 M NH 3 : [NH 3 ] = 0.1 M. Reaction: H 3 O + (aq) + NH 3 (aq) H 2 O ( l ) + NH 4 + (aq) Large Extent c. Inventory of 0.1 M H 2 SO 4 : [H 3 O + ] = 0.1 M , [HSO 4 - ] = 0.1 M. Inventory of 0.1 M NaC 2 H 3 O 2 : [Na + ] = 0.1 M , [C 2 H 3 O 2 - ] = 0.1 M. Reaction: H 3 O + (aq) + C 2 H 3 O 2 - (aq) H 2 O ( l ) + HC 2 H 3 O 2 (aq) Large Extent d. Inventory of 0.1 M NaHSO 4 : [Na + ] = 0.1 M , [HSO 4 - ] = 0.1 M. Inventory of 0.1 M NaC 2 H 3 O 2 : [Na + ] = 0.1 M , [C 2 H 3 O 2 - ] = 0.1 M. Reaction: HSO 4 - (aq) + C 2 H 3 O 2 - (aq) SO 4 -2 (aq) + HC 2 H 3 O 2 (aq) Large Extent e. Inventory of 0.1 M NH 4 Cl: [NH 4 + ] = 0.1 M , [Cl - ] = 0.1 M. Inventory of 0.1 M NaOH: [Na + ] = 0.1 M , [OH - ] = 0.1 M. Reaction: NH 4 + (aq) + OH - (aq) H 2 O ( l ) + NH 3 (aq) Large Extent f. Inventory of 0.1 M NaHCO 3 : [Na + ] = 0.1 M , [HCO 3 - ] = 0.1 M. Inventory of 0.1 M KOH: [Li + ] = 0.1 M , [OH - ] = 0.1 M. Reaction: HCO 3 - (aq) + OH - (aq) H 2 O ( l ) + CO 3 -2 (aq) Large Extent g. Inventory of 0.1 M HC 2 H 3 O 2 : [HC 2 H 3 O 2 ] = 0.1 M. Inventory of 0.1 M NaC 2 H 3 O 2 : [Na + ] = 0.1 M , [C 2 H 3 O 2 - ] = 0.1 M. Reaction: HC 2 H 3 O 2 (aq) + C 2 H 3 O 2 - (aq) ssd C 2 H 3 O 2 - (aq) + HC 2 H 3 O 2 (aq) NOTE: This reaction is between the strongest acid and the strongest base present in appreciable amount but as the reactants and products are the same, the reaction goes nowhere! h. Inventory of 0.1 M HC 2 H 3 O 2 : [HC 2 H 3 O 2 ] = 0.1 M. Inventory of 0.1 M MgSO 4 : [Mg(H 2 O) 6 +2 ] = 0.1 M , [SO 4 -2 ] = 0.1 M. Reaction: HC 2 H 3 O 2 (aq) + SO 4 -2 (aq) C 2 H 3 O 2 - (aq) + HSO 4 - (aq) Small Extent i. Inventory of 0.1 M HC 2 H 3 O 2 : [HC 2 H 3 O 2 ] = 0.1 M. Reaction: HC 2 H 3 O 2 (aq) + H 2 O ( l ) C 2 H 3 O 2 - (aq) + H 3 O + (aq) Small Extent j. Inventory of pure HNO 3 is HNO 3. Inventory of pure NaOH is NaOH. Reaction: HNO 3 ( l ) + NaOH (s) H 2 O ( l ) + Na + (aq) + NO 3 - (aq) Large Extent
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