Unformatted text preview: θ determines the flight time; let t max represent the maximum flight time. What is the least speed the ball will have during its flight if θ is chosen such that the flight time is 0.750 t max ? When the ball comes back to the ground level, the vertical displacement is zero. The flight time is 0 = v sin θ t(1/2)gt 2 t f = 2v sin θ /g The sine function takes its maximum value (= 1) when θ is 90º. Thus the maximum flight time is t max = 2v /g Since we have to choose the projection angle so that t f = 0.75t max , the angle is 2v sin θ /g = 0.75(2v /g) sin θ = 0.75 θ = 48.6º The speed of the ball takes the minimum value at the peak of the projectile motion, where y component of the velocity is zero. Therefore, the least speed is v min = v 0x = v cos θ = 35.8 m/s...
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This note was uploaded on 12/10/2011 for the course PHY 2048 taught by Professor Field during the Spring '08 term at University of Florida.
 Spring '08
 Field

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