qz2sol_1243Hs11 - a What is the magnitude of the...

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TA: Tomoyuki Nakayama Wednesday, February 9, 2011 PHY 2048: Physic 1, Discussion Section 1243H Quiz 2 (Homework Set #4) Name: UFID: Formula sheets are not allowed. Do not store equations in your calculator. You have to solve problems on your own; memorizing final algebraic expressions from homework assignments and just plugging numbers into them will not give you full credit. Leave all your work. ________________________________________________________________________________ An airplane of mass m = 1.50 × 10 4 kg is flying in a horizontal circle at a speed of 400 km/h. Its wings are tilted at angle θ = 30.0° to the horizontal. The required force for the circular motion is provided entirely by an “aerodynamic lift” that is perpendicular to the wing surface.
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Unformatted text preview: a) What is the magnitude of the aerodynamic lift? The plane is flying in a horizontal circle. Hence the vertical component of the acceleration is zero. Newton’s 2 nd law applied to the vertical direction yields 0 = Ncos θ – mg ⇒ N = mg/cos θ = 1.70 × 10 5 N b) What is the radius of the circle in which the plane is flying? First we express the speed of the plane in SI units. 400 km/h = 111.1 m/s Since the plane is moving in a circle, the component of the acceleration toward the center is v 2 /R. We apply Newton’s 2 nd law in the radial direction and solve the equation for the radius. m(v 2 /R.) = Nsin θ R = mv 2 /(Nsin θ ) = 2.18 × 10 3 m...
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