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Unformatted text preview: a) What is the magnitude of the aerodynamic lift? The plane is flying in a horizontal circle. Hence the vertical component of the acceleration is zero. Newtons 2 nd law applied to the vertical direction yields 0 = Ncos mg N = mg/cos = 1.70 10 5 N b) What is the radius of the circle in which the plane is flying? First we express the speed of the plane in SI units. 400 km/h = 111.1 m/s Since the plane is moving in a circle, the component of the acceleration toward the center is v 2 /R. We apply Newtons 2 nd law in the radial direction and solve the equation for the radius. m(v 2 /R.) = Nsin R = mv 2 /(Nsin ) = 2.18 10 3 m...
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This note was uploaded on 12/10/2011 for the course PHY 2048 taught by Professor Field during the Spring '08 term at University of Florida.
 Spring '08
 Field

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