Unformatted text preview: a) What is the magnitude of the aerodynamic lift? The plane is flying in a horizontal circle. Hence the vertical component of the acceleration is zero. Newton’s 2 nd law applied to the vertical direction yields 0 = Ncos θ – mg ⇒ N = mg/cos θ = 1.70 × 10 5 N b) What is the radius of the circle in which the plane is flying? First we express the speed of the plane in SI units. 400 km/h = 111.1 m/s Since the plane is moving in a circle, the component of the acceleration toward the center is v 2 /R. We apply Newton’s 2 nd law in the radial direction and solve the equation for the radius. m(v 2 /R.) = Nsin θ R = mv 2 /(Nsin θ ) = 2.18 × 10 3 m...
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 Spring '08
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 Force, Mass, Aerodynamics, Wing, Lift, Airfoil

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