qz2sol_3705s11 - attached to a hanging cylinder of mass M =...

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TA: Tomoyuki Nakayama Monday, February 6, 2011 PHY 2048: Physic 1, Discussion Section 3705 Quiz 2 (Homework Set #4) Name: UFID: Formula sheets are not allowed. Do not store equations in your calculator. You have to solve problems on your own; memorizing final algebraic expressions from homework assignments and just plugging numbers into them will not give you full credit. Leave all your work. ________________________________________________________________________________ A puck of mass m = 1.50 kg slides in a circle of radius r = 30.0 cm on a frictionless table while
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Unformatted text preview: attached to a hanging cylinder of mass M = 4.00 kg by a cord through a hole in the table. The hanging cylinder is at rest. a) What is the tension in the cord? Taking the positive direction downward, we apply Newton’s 2 nd law to the cylinder 0 = Mg-T ⇒ T = Mg = 39.2 N b) What is the speed (in m/s) of the puck? The puck is moving in a circle. Hence it accelerates with centripetal acceleration v 2 /R toward the center. Taking our positive direction toward the center, Newton’s 2 nd law yields m(v 2 /R) = T v = √ (TR/m) = 2.80 m/s...
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This note was uploaded on 12/10/2011 for the course PHY 2048 taught by Professor Field during the Spring '08 term at University of Florida.

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