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Unformatted text preview: Newtons 2 nd law yields M(g/6) = T Mg T = 5Mg/6 = 122.5 N In our coordinate system, the displacement of the block is d. Thus the work done by the tension is W T = T(d) = 245 J Note that the sign of work does not depend on your coordinate system. It is always negative if force and displacement are directed in opposite directions. b) When the block has fallen a distance d = 2.00 m, what is the speed of the block? The net force exerted on the block is F net = M(g/6) The initial kinetic energy of the block is zero. The workenergy theorem yields K = W net (1/2)Mv 2 0 = M(g/6)(d) v = (2(g/6)d) = 2.56 m/s...
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This note was uploaded on 12/10/2011 for the course PHY 2048 taught by Professor Field during the Spring '08 term at University of Florida.
 Spring '08
 Field

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