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Unformatted text preview: 0.2 kg. The box is open at the top and has edge length L = 40 cm. a) Find the x coordinate of the center of mass of the box. A symmetrical object has its center of mass at its geometrical center. Therefore, we treat the cubical box as a 5particle system in which each particle locates at the center of each plate. By definition, xcomponent of the com of the 5particle system is x com = [m×0 + 2m(L/2) + M(L/2) + mL]/(4m + M) = L/2 = 20 cm b) Find the z coordinate of the center of mass of the box. Using the definition of com, zcoordinate of the cner of mass is z com = [M×0 + 4m(L/2)]/(4m + M) = 14.5 cm...
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This note was uploaded on 12/10/2011 for the course PHY 2048 taught by Professor Field during the Spring '08 term at University of Florida.
 Spring '08
 Field

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