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qz7sol_6942s11 - y direction a In unit-vector notation what...

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TA: Tomoyuki Nakayama Monday, March 21, 2011 PHY 2048: Physic 1, Discussion Section 6942 Quiz 7 (Homework Set #9) Name: UFID: Formula sheets are not allowed. Do not store equations in your calculator. You have to solve problems on your own; memorizing final algebraic expressions from homework assignments and just plugging numbers into them will not give you full credit. Leave all your work. ________________________________________________________________________________ A 4.00 kg particle with velocity v = (3.00 m/s) i - (2.00 m/s) j + (4.00 m/s) k is at x = 6.00 m, y = 0 m, z = 0 m. It is pulled by a 15.0 N force in the positive
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Unformatted text preview: y direction. a) In unit-vector notation, what is the particle's angular momentum about the origin? By definition, the angular momentum of the particle is l = r × m v =m(yv z- zv y ) i + m(zv x- xv z ) j + m(xv y- yv x ) k = -96(kg · m 2 /s) j- 48(kg · m 2 /s) k b) In unit-vector notation, what is the rate at which the angular momentum is changing? According to Newton’s 2 nd law in angular form, the rate of change in the angular momentum of the particle is equal to the torque acting on the particle. d l /d t = τ = r × F =(yF z- zF y ) i + (zF x- xF z ) j + (xF y- yF x ) k = 90(N · m) k...
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