Unformatted text preview: waterline. a) What is the mass of the water pumped out of the basement in one second? During time interval Δ t, the mass of the water pumped out of the basement is Δ m = ρΔ V = ρπ (d/2) 2 v Δ t Therefore, the mass of the water pumped out in one second is Δ m/ Δ t = ρπ (d/2) 2 v = 1.57 kg/s b) What is the power of the pump? The work-energy theorem yields W = Δ E = Δ K + Δ U = (1/2) Δ mv 2 + Δ mgh, where W is the work done by the pump. Since the power of the pump is defined as the work done by the pump in one second, we have P = W/ Δ t = (1/2)( Δ m/ Δ t)v 2 + ( Δ m/ Δ t)gh = 65.8 W...
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This note was uploaded on 12/10/2011 for the course PHY 2048 taught by Professor Field during the Spring '08 term at University of Florida.
- Spring '08