f11smid2

f11smid2 - mR 2 sin 2 = M z . angular momentum...

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SOLUTIONS MIDTERM PHY 4936 (Fall 2011) PROBLEM 2 2.1 In sperical coordinates with r = R = const L = m 2 R 2 ± ˙ φ 2 sin 2 θ + ˙ θ 2 ² - mg R cos θ . 2.2 The conservations laws are E = m 2 R 2 ± ˙ φ 2 sin 2 θ + ˙ θ 2 ² + mg R cos θ energy conservation and p φ = ∂L ˙ φ =
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Unformatted text preview: mR 2 sin 2 = M z . angular momentum conservation. 3.3 Special solution ( t ) = = const : = M z mR 2 sin 2 = ( t ) = t + ....
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This note was uploaded on 12/11/2011 for the course PHY 4936 taught by Professor Berg during the Fall '11 term at FSU.

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