Formula_sheet (3) - e = 1.60 10 19 C me = 9.11 10 31 kg F...

Info icon This preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon
kg m C e e 31 19 10 11 . 9 ; 10 60 . 1 - - = = 2 2 12 0 2 2 9 0 2 2 1 / 10 85 . 8 / 10 99 . 8 4 1 m N C C m N k r Q Q k F = = = = - ε πε E q F = ... ... 2 1 2 1 + + = + + = E E E F F F net net ____________________________ 0 4 cos ε π θ encl encl E E E Q kQ d A d E dA E d = = Φ = = Φ = Φ Point charge: 2 0 4 r Q E πε = Long cylinder: L Q r E = = λ πε λ ; 2 0 Plane surface and capacitor: A Q E = = σ ε σ ; 0 Infinite sheet: A Q E = = σ ε σ ; 2 0 ( 29 3 0 2 / : Dipole y p E πε = Q W Q U U V V V ba a b a b - = - = - = θ cos || Ed Ed V - = - = gradV V z V k y V j x V i E dz E dy E dx E l d E dV z y x - -∇ + + - = + + = - = ˆ ˆ ˆ Point charge: r Q k V V = - qd p r p k V = = ; cos : Dipole 2 θ V Q C = Plane capacitor: d A C 0 ε = Dielectrics: 0 0 ; ε ε K KC C = 2 2 1 2 2 1 2 2 1 2 1 E u C Q CV QV U ε = = = = Capacitors in parallel: Q Q Q V V V C C C eq = + + = = = + + = ... ... ... 2 1 2 1 2 1 Capacitors in series: Q Q Q V V V C C C eq = = = = + + + + = ... ... ... 1 1 1 2 1 2 1 2 1 dt dQ I = ; θ cos dA dI J = ; A d J dI = I V R / = L A R = σ ρ 1 ; J E ρ = ; E J σ = ; [ ] ) ( 1 0 0
Image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Image of page 2
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern