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Unformatted text preview: EE221A Problem Set 4 Solutions  Fall 2011 Problem 1. Existence and uniqueness of solutions to differential equations. Call the first system f ( x,t ) = x 1 x 2 T and the second one g ( x ) = x 1 x 2 T . a) Construct the Jacobians: D 1 f ( x,t ) = 1 e t sin( x 1 x 2 ) e t sin( x 1 x 2 ) 15cos( x 1 x 2 ) 1 15cos( x 1 x 2 ) , Dg ( x ) = 1 + x 2 x 1 1 . D 1 f ( x,t ) is bounded x , and f ( x,t ) is continuous in x , so f ( x ) is globally Lipschitz continuous. But while g ( x ) is continuous, Dg ( x ) is unbounded (consider the 1,1 entry as x 2 or the 1,2 entry as x 1 ) so the function is not globally LC. b) Agree. Note that x 2 does not depend on x 1 ; it satisfies the conditions of the Fundamental Theorem, and one can directly find the (unique by the FT) solution x 2 ( t ) = x 2 (0) e t as t . This solution for x 2 can be substituted into the first equation to get x 1 = x 1 + x 1 x 2 (0) e t = x 1 ( x 2 (0) e t 1 ) , which again satisfies the conditions of the Fundamental Theorem, and can be solved to find the unique solution...
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 Fall '10
 ClaireTomlin

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