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Unformatted text preview: EXAM—ll Name ENMElloSTATICS Panes G. Charalambides
December 8, 2011 PART A: (30 points) 1. The internal force N shown is, (a) a compressive force of magnitude 14.14 KN.
(b) a tensile force of magnitude 14.14 KN. (c) a zero force member. 2. The truss member BE is (a) in tension. (b) is a zero force member. (0) in compression. 3. For the beam shown, the bending moment diagram at the location of the external applied moment M
when moving in the positive x direction, exhibits, (a) an upward jump equal to the applied external moment. (b) a downward jump equal to the applied external moment. (c) a smooth transition from the left to the right of the applied moment.
2000 lbs 3Q w(x)=1t}{}0 lb/Ft 4. Assuming impending motion at all contact points, the correct free body diagram for the beam shown is (a) fbd “a” (b) Ibd “b” (c) fbd “c”
F“ F1; F"
NE
4—— +~— \. \e
............... {ltbdj “3”) —»............., (thd are”) F" NA NA NA 5. The correct positive shear force V and bending moment M acting at a section are shown in,
(3) M (a) shematic (a). El[ DC (JE
(b) shernatic (b). v M M V _
A :—b (i—
(C) shematic (c). v v
M m
ED (IE1
V V 6. The tipping load Pup is, (a) w equal to Whiz!» , g"
(b) M—Wm is less than Wb/Zlq, h
(C) —mm_ equal \VXIZLL —*— 7. The flat belt shown is subject to end forces T1=300N and T2=200N. The coefﬁcient of static friction at the contact surface is u5=0.3. Under the above conditions, the belt will
direction of potential motion (a) move in the direction of T1.
(b) move in the direction of ’1‘2. Ti Z300 N “5:03
(c) remain stationary. T2 =2oo N 8. Assuming impending motion at all contact points, the correct free body diagram for the wedge shown is (a) fbd (a) (b) fbd (b) (c) fbd (c) 9. Assuming constant density, the center of gravity for the composite areas show is located A Y (a) above the x axis.
(b) on the x—axis. C x
(0) below the xaxis. A ” c
ml..._
a v  _.H .1
c c 10. When comparing the second moment of inertia Ixx for the two composite areas shown,
one can conclude that, (a) mi: =15:
(b) m1: >13;
to) W1: <13; Bonus Question 1 l. A rectangular panel of height h and width w is used as a gate submerged in depths z] and 22 as showu. When calculating
the total forces F1 and F2 exerted on gate 1 and gate 2 respectively due to the water pressure one can conclude that, (a) W F] 31:2
('3) H F] >132 (C) m Fr <1”; December 8, 2011
Exam IIPART BProblem # 1 25/100 Points Name: The twomember structure is connected at C by a pin which is ﬁxed to BDE and passes through the smooth
slot in member AC. Determine the reaction forces at supports D and E. 500 lb “you lb  ft 4‘ l~—~——~ 3 r: % ﬁ 3 nmm—T— 2 n —» December 8, 2011
Exam IIPART BPr0blem # 1 (page 2) Name: December 8, 2011
Exam IIPART BProblem # 2 (25/100 Points) Name: Gate ABC has a constant Width W and is supported through a hing at B. Determine the length L in terms
of hI and 112 so that the gate remains in its closed position without any assistance from reaction forces at A and C. December 8, 2011
Exam IIPART BPr0blem # 2 (page 2) Name: December 8, 2011 Exam IIPART BProblem # 3 (20/100 Points Name: For the beam shown in the ﬁgure below, (a) Find the reaction forces at supportsA and D. (b) Derive the shear force and bending moment equations in the interval between section A and B. (C) Show that the derivative of the moment equation derived in (b) yields the shear force equation
in the same interval. )1 l w(x)=10 KN/m 20 KN December 8, 2011
Exam IIPART BPr0blem # 3 (page 2) Name: ...
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