2_Ch 16 College Physics ProblemCH16 Electrical Energy and Capacitance

2_Ch 16 College Physics ProblemCH16 Electrical Energy and Capacitance

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
36 CHAPTER 16 7. (a) C decreases. (b) Q stays the same. (c) E stays the same. (d) V increases. (e) The energy stored increases. Because the capacitor is removed from the battery, charges on the plates have nowhere to go. Thus, the charge on the capacitor plates remains the same as the plates are pulled apart. Because 00 QA E σ == ∈∈ , the electric field is constant as the plates are separated. Because V = Ed and E does not change, V increases as d increases. Because the same charge is stored at a higher potential difference, the capacitance has decreased. Because 2 2 QC = Energy stored and Q stays the same while C decreases, the energy stored increases. The extra energy must have been transferred from somewhere, so work was done. This is consistent with the fact that the plates attract one another, and work must be done to pull them apart. 8. (a) C increases. (b) Q increases. (c) E stays the same. (d) V remains the same. (e) The energy stored increases.
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 12/09/2011 for the course PHYS 2020 taught by Professor Staff during the Fall '10 term at FIU.

Ask a homework question - tutors are online