178CHAPTER 20 46.(a)2.00 ms (b)0.176 A (c)1.50 A (d)3.22 ms 48.(a)4.44(b)5310H−×4.5510J−×50.(a)2LRτ=(b)2=52.3100 A, the galvanometer will definitely show the induced currentµ54.(a)Amplitude doubles, period unchanged. (b)Amplitude doubles, period cut in half. (c)Amplitude unchanged, period cut in half. 56.(a)(b)106.2510J×2.00 kN m 58.0.121 A, clockwise
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This note was uploaded on 12/09/2011 for the course PHYS 2020 taught by Professor Staff during the Fall '10 term at FIU.