Induced Voltages and Inductance179Problem Solutions 20.1The magnetic flux through the area enclosed by the loop is ( )()( )222coscos00.30 T0.25 m5.910T mBBABrθππ−Φ==°==×⋅220.2The magnetic flux through the loop is given by cosBBAθΦ=where Bis the magnitude of the magnetic field, Ais the area enclosed by the loop, and is the angle the magnetic field makes with the normal to the plane of the loop. Thus, 527210cos5.0010T20.0 cm1.0010T mcosBBA2-2mcos1 cmθθ−−=××⋅=(a) When Bis perpendicular to the plane of the loop, JG0=°and 7210T mB−×⋅1.00(b) If 830.0 , then 1.0010T mcos30.08.6610T mBΦ= ×⋅°⋅2=°(c) If ( )90.0 , then 1.0010T mcos90.00B−Φ⋅°=20.3The magnetic flux through the loop is given by cosBBAΦ=where Bis the magnitude of the magnetic field, Ais the area enclosed by the loop, and is the angle the magnetic
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This note was uploaded on 12/09/2011 for the course PHYS 2020 taught by Professor Staff during the Fall '10 term at FIU.