5_Ch 20 College Physics ProblemCH20 Induced Voltages and Inductance

# 5_Ch 20 College Physics ProblemCH20 Induced Voltages and Inductance

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Induced Voltages and Inductance 179 Problem Solutions 20.1 The magnetic flux through the area enclosed by the loop is ( ) ( ) ( ) 2 2 2 cos cos0 0.30 T 0.25 m 5.9 10 T m B BA B r θ π π Φ = = ° = = × 2 20.2 The magnetic flux through the loop is given by cos B BA θ Φ = where B is the magnitude of the magnetic field, A is the area enclosed by the loop, and θ is the angle the magnetic field makes with the normal to the plane of the loop. Thus, ( ) ( ) 5 2 7 2 10 cos 5.00 10 T 20.0 cm 1.00 10 T m cos B BA 2 -2 m cos 1 cm θ θ θ Φ = = × × = (a) When B is perpendicular to the plane of the loop, JG 0 θ = ° and 7 2 10 T m B Φ = × 1.00 (b) If ( ) 7 2 8 30.0 , then 1.00 10 T m cos30.0 8.66 10 T m B Φ = × ° = × 2 θ = ° (c) If ( ) 7 2 90.0 , then 1.00 10 T m cos90.0 0 B Φ = × ° = θ = ° 20.3 The magnetic flux through the loop is given by cos B BA θ Φ = where B is the magnitude of the magnetic field, A is the area enclosed by the loop, and
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