5_Ch 23 College Physics ProblemCH23 Mirrors and Lenses

5_Ch 23 College Physics ProblemCH23 Mirrors and Lenses - or...

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Mirrors and Lenses 271 Problem Solutions 23.1 If you stand 40 cm in front of the mirror, the time required for light scattered from your face to travel to the mirror and back to your eye is () 9 8 20 .40 m 2 2.7 10 s 3.0 10 m s d t c ∆= = = × × Thus, the image you observe shows you 9 ~10 s younger than your current age. 23.2 θ θ ′ = since they are vertical angles formed by two intersecting straight lines. Their complementary angles are α α ′ = . The right triangles PQR and P'QR have the common side QR and are then congruent by the angle-side-angle theorem. Thus, the corresponding sides PQ and P'Q are equal, or the image is as far behind the mirror as the object is in front of it. ±²³´µ¶ ·¸¹º´ »¼½½¾½ ± ± ± ² ±³ ² ² ± ± ± ± ± 23.3
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Unformatted text preview: or 10.0 ft from the person (2) The first image in the right-hand mirror serves as an object for the left-hand mirror. It is located 10.0 ft behind the right-hand mirror, which is 25.0 ft from the left-hand mirror. Thus, the second image in the left-hand mirror is 25.0 ft behind the mirror, or 30.0 ft from the person (3) The first image in the left-hand mirror serves as an object for the right-hand mirror. It is located 20.0 ft in front of the right-hand mirror and forms an image 20.0 ft behind that mirror. This image then serves as an object for the left-hand mirror. The distance from this object to the left-hand mirror is 35.0 ft. Thus, the third image in the left-hand mirror is 35.0 ft behind the mirror, or 40.0 ft from the person...
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This note was uploaded on 12/09/2011 for the course PHYS 2020 taught by Professor Staff during the Fall '10 term at FIU.

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