238CHAPTER 22 Problem Solutions 22.1The total distance the light travels is Therefore, ()86622 3.84106.38101.7610m7.5210 mcenter toEarthMooncenterdDR R∆=−−=×−×−× =×8887.523.0010 m s2.51 sdvt∆×===×∆22.2If the wheel has 360 teeth, it turns through an angle of 1in the time it takes the light to make its round trip. From the definition of angular velocity, we see that the time is 720 rev( )51720 rev5.0510s27.5 rev stθω−=×Hence, the speed of light is ( )
This is the end of the preview. Sign up
access the rest of the document.