7_Ch 15 College Physics ProblemCH15 Electric Forces and Electric Fields

7_Ch 15 College Physics ProblemCH15 Electric Forces and Electric Fields

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Electric Forces and Electric Fields 7 Problem Solutions 15.1 Since the charges have opposite signs, the force is one of attraction . Its magnitude is ( )( ) () 99 2 12 9 8 2 22 4.5 10 C 2.8 10 C Nm 8.99 10 1.1 10 N C 3.2 m e kqq F r −− ××  == × = ×   15.2 The electrical force would need to have the same magnitude as the current gravitational force, or 2 giving E moon E moon e
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