7_Ch 16 College Physics ProblemCH16 Electrical Energy and Capacitance

7_Ch 16 College Physics ProblemCH16 Electrical Energy and Capacitance

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Electrical Energy and Capacitance 41 Problem Solutions 16.1 (a) The work done is ( ) cos cos WF s q Es θ =⋅ = () , or ( )( ) 19 2 19 1.60 10 C 200 N C 2.00 10 m cos0 6.40 10 J W −− × ° (b) The change in the electrical potential energy is 19 6.40 10 J e PE W ∆= −= − × (c) The change in the electrical potential is 19 -19 6.40 10 J 4.00 V 1.60 10 C e PE V q −× = =− × 16.2 (a) We follow the path from (0,0) to (20 cm,0) to (20 cm,50 cm). The work done on the charge by the field is ( ) ( ) () () 12 1 1 2 2 64 cos cos 0.20 m cos0 0.50 m cos90 12 10 C 250 V m 0.20 m 0 6.0 10 J WW W q q qE θθ =+= ⋅ + ⋅ + °   +=× Thus, 4 6.0 10 J e PE W
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